Python中的min及返回最小值索引的操作

def indexofMin(arr):
    minindex = 0
    currentindex = 1
    while currentindex < len(arr):
        if arr[currentindex] < arr[minindex]:
            minindex = currentindex
        currentindex += 1
    return minindex
arr = [3,5,2,1]
print(indexofMin(arr))

n = max(list) #list 表示要返回最大值的列表。

list1 = [123, 456, 789]
list2 = ['123', '456', '789']
list3 = ['abc', 'abb', 'acb']

print(max(list1))  #789
print(max(list2))  #789
print(max(list3))  #acb

list1.index(max(list1))

list1 = [123, 456, 789]
print(list1.index(456))  #1
print(list1.index(max(list1))) #2